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0.01x^2+5x+200=0
a = 0.01; b = 5; c = +200;
Δ = b2-4ac
Δ = 52-4·0.01·200
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{17}}{2*0.01}=\frac{-5-\sqrt{17}}{0.02} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{17}}{2*0.01}=\frac{-5+\sqrt{17}}{0.02} $
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